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Find the y-coordinate of the vertex for the following function: g(x) = x2 - 3x + 2 y= its asking for a simplified fraction?
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you might want to put it into vertex form by completing the square. \[x^2 -3x +(\frac{3}{2})^{2 }+2-(\frac{3}{2})^{2}=\] \[(x-\frac{3}{2})^{2}+(-\frac{1}{4})\]
so we see that the vertex is( 3/2,-14)
so the fraction would be 3/2?
when x=3/2; what does y=?
-1/4 ; he dropped the bar
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oh, lol thank you!
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