Question

Let y = 1/x^4. Find values A and B so that (dy)/(dx) = A/(x^B).

A =
B =

Answer 1

\[y=x^{-4} => y'=(-4)x^{-4-1}=-4 \cdot \frac{1}{x^5}=\frac{-4}{x^5}\]

Answer 2

can you identify A and B now?

Answer 3

is the formula to solve for a?

Answer 4

what do I need to do after -4/ x^5?

Answer 5

identify A and B

Answer 6

\[y'=\frac{-4}{x^5}=\frac{A}{x^B}\]

Answer 7

so A=?
and B=?

Answer 8

-4=a?
and

Answer 9

b= x^5?

Answer 10

A=-4 is right
but B does not equal x^5

Answer 11

b= 5

Answer 12

B=5