Question

what is the value of f'(x) = A x^B when f(x) = 3/x^11?

Answer 1

\[y=3x^{-11}\]
use power rule

Answer 2

wait how did you get the -11

Answer 3

thats what I put and its says its wrong

Answer 4

a=?
b=?

Answer 5

so you used the power rule ?

Answer 6

and what did you get?

Answer 7

for some reason A is not =3

Answer 8

yeah that is because A does not =3 and B does not -11

Answer 9

I got -3x^10

Answer 10

you need to use the power rule for
\[y=3x^{-11}\]

Answer 11

bring down the -11
and then subtract 1 from the exponenet

Answer 12

\[y'=3(-11)x^{-11-1}\]
just like i did here

Answer 13

11X3=33 so it would be 33x^10?

Answer 14

am i right?

Answer 15

ok im right nevermind thanks

Answer 16

no
\[y'=-33x^{-12}\]

Answer 17

-33X^-12

Answer 18

Im meant that

Answer 19

-11-1=-12
3(-11)=-33