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OpenStudy (anonymous):
the range is all reals
OpenStudy (anikate):
huh?
OpenStudy (anonymous):
(-infinity, 0) (0, infinity)
OpenStudy (anikate):
what?
OpenStudy (anikate):
i dont get it
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OpenStudy (anikate):
keep goig i'l try to figure it out
OpenStudy (anonymous):
There are no restrictions to the range
OpenStudy (anikate):
um... need to find range is all i no
OpenStudy (anonymous):
Okay, well you could always substitute 0 for the x value and work out the whole question from there. However, the answer I gave you earlier should be correct
OpenStudy (anikate):
what was the answer u gave earlier?
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OpenStudy (anikate):
-3.5?
OpenStudy (anonymous):
All real numbers. The domain would be all real numbers, and so should the range
OpenStudy (anikate):
what r real numbers?
OpenStudy (anonymous):
Or, you could set y= 0 and work out the whole equation
OpenStudy (anikate):
then what would be my answer?
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OpenStudy (anikate):
-3.5?
OpenStudy (anonymous):
For instance,
(0= 2x - 7/ 2 ) x 2
0= 4x-14
14=4x
14/4=x
OpenStudy (anonymous):
That's solving for x
OpenStudy (anikate):
range is always y right?
OpenStudy (anonymous):
Substitution with x and zero would look like this:
y= 2(0) -7/2
y= -5/2
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OpenStudy (anonymous):
that is the range when solving the equation
OpenStudy (anikate):
actually it would be -3.5
OpenStudy (anonymous):
Well, if you were trying to be precise, then yes. However, most math classes perfer that you leave it in the fractional form.
OpenStudy (anikate):
idk the range when soling equatyion. and i know
OpenStudy (anonymous):
also it should be -2.5, not -3.5
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OpenStudy (anikate):
how
?
OpenStudy (anonymous):
2-7 = -5
-5 divided by 2 = -2.5
OpenStudy (anikate):
y=2(0)-7/2
y=0-7/2
y=-3.5
OpenStudy (anonymous):
oh, I just got served! You are absolutely right my dear. Thanks for catching my mistake ;}
OpenStudy (anikate):
oh it's k np
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