Question

Assume that there are 8 different issues
of Popular Science, 7 different issues of Time,
and 4 different issues of Sports Illustrated, including
the December 1st issue, on the rack. You
choose 4 of them at random.
(1) What is the probability that you choose 3
issues of Popular Science and 1 issue of Time?
(2) What is the probability that you choose at
least 3 of the Time magazines?

Answer 1

P(1) = 4C3 * (7/19)*(8/18)*(7/17)*(6/16)

Answer 2

P(3 PS and 1 Ti) = [C(8,3)C(7,1)] / C(19,4) = 98/969 = .101 approx

Answer 3

no

Answer 4

that didnt work

Answer 5

See if you wrote the problem correctly. I was expecting a restriction about the Dec 1 SI.

Answer 6

Mr. Cow has 98/969 = .101 approx

Answer 7

it never specifies the 1 december 1st issue

Answer 8

On the first part, Mr. Cow and I agree. Check every word of the problem.

Answer 9

98/969 is correct
.101 is not

Answer 10

same thing right

Answer 11

yes, are you to leave answers as fractions?

Answer 12

i guess so it only worked with 969 but says .101
i tried it multiple times haha

Answer 13

the next one does specify

Answer 14

for next part
-> .1174 or 455/3876

Answer 15

Genius guys

Answer 16

2) at least 3 T

[C(7,3) C(8,1) + C(7,3)C(4,1) +C(7,4)] / C(19,4) = 455 / 3 876 = .117 approx

Answer 17

You are a genius guy. What's up with my fraction. I'll check.

Answer 18

thank you so much man
you have helped save me