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Mathematics 16 Online
OpenStudy (anonymous):

Show that p ^ ~p is a contradiction.

OpenStudy (anonymous):

It's true!

OpenStudy (anonymous):

p xor not p is always true

OpenStudy (anonymous):

oh..... you meant p and not p...... that's false

OpenStudy (jamesj):

if p = true, i.e., T, then p ^ ~p = T ^ ~T = T ^ F = F Similarly if p = F.

OpenStudy (anonymous):

from the statement of p and not p, it is clear that either p or not p has to be false, so the result is naturally false.

OpenStudy (anonymous):

Ok thanks guys. I see the correlation now.

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