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What is the equation of the oblique asymptote? h(x)=(x²-3x-4)/(x+1)
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x²-3x-4 factors
Factor x^2 -3x -4 = (x+1)(x-4)
opps I meant to add a. y=x b. y=x+4 c. y=x-4 d. y=x²-3
???
you, pretty much, have been given the answer
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y=x-4
you divide numerator by denominator. The result will be oblique asymptote
More information on oblique or slant asymptotes: http://www.purplemath.com/modules/asymtote3.htm http://www.purplemath.com/modules/asymnote.htm
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