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Evaluate the integral: e^(5x)cos(e^5x) with an upper limit of 3 and lower limit of 0
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substitution: u = e^5x du = 5*e^5x dx --> dx = du/5e^5x --> integral (1/5) cos(u) du
I got sin e^5-sin 1/5 but I think it is supposed to be a decimal number i have no idea how to go about this
i think it should be sin(e^15) ....5x evaluated at x=3 yes i get 0.029, just use a calculator to get approximate answer, should be in radians
got it, thanks. I see where I went wrong.
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