Can someone plz help me out with inequality using polar coordinates?

Question

Can someone plz help me out with inequality  using polar coordinates?

anonymous · Answer

attachment

turingtest · Answer

um... not really sure if I get the question, but the area swept out by r is$$\frac38\le r\le\frac12$$and theta is just$$0\le\theta\le2\pi$$

turingtest · Answer

no sorry inner r is 3/16

turingtest · Answer

$$\frac3{16}\le r\le\frac12$$$$0\le\theta\le2\pi$$I suppose

anonymous · Answer

yes that is the answer

turingtest · Answer

do you need explanation?

anonymous · Answer

lol yes i dont understand how u got thise values

turingtest · Answer

well polar coordinates are defined with radius and angle. Here are the diameters|dw:1329346620272:dw|so we know the radii are half this.
therefor radius of any point on the washer is between 3/16inches (the radius of the inner circle) and 1/2inches (the radius of the outer circle)$$\frac3{16}\le r\le\frac12$$

anonymous · Answer

ok got that

turingtest · Answer

|dw:1329346791420:dw|as for the angle, the washer is circular, so the angle has to sweep out a complete circle:$$0\le\theta\le2\pi$$(we never go around the circle more than once, so no need to put more than 2pi))