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Use the Quadratic Formula to solve the equation. 6 + 6x – x^2 = 0
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i got an answer involving a square root and got it wrong :(
\[x=\frac{-6\pm \sqrt{6^2-4(-1)(6)}}{-2}\]
after that i got (-6+-√60)/2
do you think the final answer should be (-6+-2√15)/2
\[x=\frac{-6\pm \sqrt{60}}{-2}\]
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\[x=\frac{-6\pm2\sqrt{15}}{-2}\]
should i divide the 6 by 2?
-6/-2?
\[x=3\pm \sqrt{15}\]
i was under the impression i was not to touch the number that is next to the radical if it is not seperated by a +- sign
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You have two terms in the numerator. They can be reduced individually
oo ok, thanks for your help
\[x=\frac{-6}{-2}\pm\frac{2\sqrt{15}}{-2}\]
yw
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