Question

find the equation of a circle in standard form where 6,-2 and -4,4 are endpoints of a diameter

Answer 1

help....

Answer 2

The length of the diameter is (used the distance formula) = 2 times Square Root of 34.

The radius is, then, √ (34)

The midpoint of the diameter is the center of the circle and will give the (h,k).

(6-4)/2 gives 1 for h and (-2+4)/2 yields 1 for k.

(x - 1) ^2 + (y - 1) ^2 = √ (34) ^2

(x - 1) ^2 + (y - 1) ^2 = 34

Answer 3

See the graph of the circle at the link:
http://www.wolframalpha.com/input/?i=%28x+-+1%29+%5E2++%2B+%28y+-+1%29+%5E2+%3D+34