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consider the following equation 7x+6y=17..find the equation in slope-intercept form, for the line which is parallel to this line and passes through the point (-6,2)
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parallel lines have the same slope. So our lie must have a slope of -7/6 Our line is, y-2=(-7/6)(x+6) rearrange to get in slope intercept form
so y=(-7/6)x-5
so the 6 in the slope and the point cancel out....then add 2 to the other side leaving -5?
in the x portion of the point, yes :)
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Parallel = same slope 7x+6y=17 => y = (17-7x)/6 => y=(17/6)-(7/6)x then m is -(7/6) (y-2)/(x+6) = -(7/6) y=-(7/6)x-5 then new y pass by (-6,2) and has slope -(7/6)
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