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Physics 6 Online
OpenStudy (anonymous):

is anyone good with mechanical advantage?

OpenStudy (anonymous):

#4, 5 & 6

OpenStudy (anonymous):

I don't know how to calculate it

OpenStudy (anonymous):

Well, I will give you a tip. You can use mechanical advantage = Force * distance. keep in mind that the force is the module of the secant vector by the axis of rotation. And the distancia and given by space between the axis of rotation and the place where the force is applied

OpenStudy (anonymous):

can you solve like one so I can have an example. cause it's easier for me to learn how to do it, when i see how it is done (:

OpenStudy (anonymous):

Sorry, I'm from brazil, here we say arm strength, then I am note sure

OpenStudy (anonymous):

hm, yep, i will try

OpenStudy (anonymous):

okay, thanks

OpenStudy (anonymous):

4,5 or 6 ?

OpenStudy (anonymous):

5

OpenStudy (anonymous):

ok i will try

OpenStudy (jamesj):

Here are the problems for anyone following along at home:

OpenStudy (anonymous):

5. biting (jaw) (I) In fact the mechanical advantage is constant, so we will call k k = 7 cm * 800 N = 5600 cmN But the distance is 10 cm, so => 5600cmN = 10 cm * F out Then F out = 560N lifting (arm) (II) Using the some concept k = 5 cm * 800 N = 4000cmN But d = 35 cm, so => 4000cmN = 35 cm * F out Then F out ~ 114 N So ! F out jam >>>> F out arma =) OBS : The unit of torque is mN but in this case i didnt converte the cm cause I'm lazy :P

OpenStudy (anonymous):

omg thank you!!

OpenStudy (anonymous):

welcome =)

OpenStudy (anonymous):

thank you for the medalls hahahaha

OpenStudy (anonymous):

np lol

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