Question

R(t) = 10 sin (30t) + 10
How would I graph this?

Answer 1

\[y=A\sin(Bx+C)\]has amplitude A, period \[\frac{2\pi}{|B|}\]and phase shift C
the graph of \[f(x)+k\]is the graph of f(x) shifted up by k units

so your graph is a sin wave with an amplitude of 10, a period of pi/15, and a phase shift of zero, moved upwards by 10 units

http://www.wolframalpha.com/input/?i=plot+y+%3D+10+sin+%2830t%29+%2B+10

Answer 2

for period, can't I just do 360/k?

Answer 3

\[2\pi\text{radians}=360^{\circ}\]so they are the same.
radians is better though, so get used to them

Answer 4

and if you mean what I called k, then no
it would be 360/B for the period

Answer 5

so it'll be 30?

Answer 6

what will be 30?

Answer 7

wait, how would I find the period? would it be 360/30? and would the maximum value be positive 10?