Question

so i need to solve this equation by useing the square root property
4x^2-28x+49=5

Answer 1

you should be able to factorise the left hand side of this equation

Answer 2

yes but the factors have to add to = 28

Answer 3

correct

Answer 4

are you stuck in the factorisation process?

Answer 5

you need to end up with something like:\[(...)^2=5\]so see if you can factorise the left hand side such that it becomes something squared, i.e.:\[4x^2-28x+49=(...)^2\]

Answer 6

the first term is \(4x^2\) and the term involving x is negative, so we know it must be of the form:\[(2x-???)^2\]

Answer 7

does any of this make sense?

Answer 8

yes thank you

Answer 9

ok - so can you see how to factorise the left hand side now?

Answer 10

yes

Answer 11

good - so you know how to solve this equation now?

Answer 12

yes