Question

X^2y'=xy-y^2

Answer 1

What r we solving for?

Answer 2

for some reason i cant simplify x^2(xv'+v)=xv-v^2 into v=
the differential eq

Answer 3

I got: x^3+x^2-x+v=0

Answer 4

idk if it's right or if I even did it right but I tried.

Answer 5

Here is a detailed explanation of the solution x and y. Y is the first picture.

Answer 6

the answer is y=x/((ln (x )+c)

i got it i made a stupid substitution for y using y=v when it should y=vx which yields a simple factor and simplification