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Given f (x) = 7x^2 + 4x - 13, A = sum of roots of f (x) = 0, B = product of roots of f (x) = 0, find ( A + B)^2
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Won't factor, use quadratic formula
not to butt in but you can find the sum of the roots and the produce of the roots without finding the roots
Alright then, the floor is yours lol
you can also prove those formulas using the quadratic formula, but sum of roots of a quadratic \[ax^2+bx+c=0\] \[r_1+r_2=-\frac{b}{a}\] produce is \[r_1r_2=\frac{c}{a}\]
*product
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The answer is 289/49. Could you please show me the steps?
product of the roots, according to satellite's formula is -13/7
sum is -4/7
\[(-\frac{13}{7}-\frac{4}{7})^2=(-\frac{17}{7})^2=\frac{289}{49}\]
Thank you so much
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could you explain how did you get the A .
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