ok i completely forgot...im setting bounds and so i set y=2x^2 to y=0... so 2x^2=0 what are my bounds? i cant think its too late lol. is it x=0 and x=?? idk. helppp

Question

dumbcow · Answer

to what are you referring?
area under curve ?

anonymous · Answer

yes

dumbcow · Answer

so the function f(x) = 2x^2 is bounded by the x_axis

dumbcow · Answer

that doesn't make sense ...the area would be infinite

anonymous · Answer

uhh now im just confused lol. im trying to find the bounds for a spinning object thing. so i suppose that would make it infinite? i dont know im so confused...

dumbcow · Answer

now its spinning, so im guessing volume?
can you post the original problem, then maybe i can help you set it up

anonymous · Answer

haha sorry. this section is kicking my butt. but yes that would help me a ton. the original problem: find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the given lines... y=2x^2, y=0, x=2

dumbcow · Answer

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what axis is it being revolved around?