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lim as x approaches 0 for f(x)=ln(x/(x-1)
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\[\frac{\ln x}{x-1}\]??
not quite, natural log of the entire fraction
\[f(x)=\ln(\frac x{x-1})\]yes?
yep
-ininity
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how did you get that?
long division\[\ln(1+\frac1{x-1})\]x goes to zero and we get\[\ln(1+(-1))=\ln 0=-\infty\]
ln is continous, so lim and ln can change places, so when you do that, and than plug in x=0 you get ln0 which is the result turing test wrote
ok that makes sense. Thank you
you're welcome :D
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