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Mathematics 21 Online
OpenStudy (cowboy):

What is the equation of the graph below? http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/C-CirclesExam/Geometry_7_Exam_81q.gif

OpenStudy (y2o2):

the equation of any circle is : \[(x-a)^2 + (y-b)^2 = r^2 \] ; a is the x coordinate of the center of the circle b a is the y coordinate of the center of the circle r is the radius of the circle. so the equation is \[(x-(-2))^2 + (y-(-4))^2 = 2^2\] \[(x+2)^2 + (y+4)^2 = 4\]

OpenStudy (cowboy):

Ah, I see what I was doing wrong there. Thanks!

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