Question

Solve using quadratic formula:
x(x-2) - 3(2x-5) = 2

...Let's just say I'm just as bad with this formula as I am with fractions.

Answer 1

well expand and simplify 1st

x^2 - 2x - 6x + 15 = 2 so x^2 -8x + 13 = 8

GQF \[(-b \pm \sqrt{b^2 - 4ac})/2a\]

a = 1, b = -8 c = 13 ... substitute and simplify. You should get

\[(-8 \pm \sqrt{10})/2\]

Answer 2

simplifyed equation should be x^2 - 6x + 13 = 0

Answer 3

The equation is simplified to
\[x^2-8x+5=0\]
a=1 b=-8 c=5
Quadrstic formula
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 4

actuually c = 13... not 8

Answer 5

Wait...
Wouldn't that be: x^2 - 8x + 13 = 0 ?