Question

Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3.

What is the volume of the balloon at time t = 25 seconds?: V =?

Answer 1

How fast is the volume changing after 25 seconds? I think this a derivative so dV/dt

Answer 2

V' = 2/(sqrt(t))

Answer 3

V= 4t^1/2 dV/dt = 2t^-1/2

Answer 4

then sum 25 for t

Answer 5

oops sub 25 for t

Answer 6

looks like +-2/5 cm3/sec

Answer 7

who asked about rate of change?

Answer 8

He did

Answer 9

me

Answer 10

Btw when t = 25, the volume is 20

Answer 11

that's all it asks as far as I can see
'What is the volume of the balloon at time t = 25 seconds?'

Answer 12

next post below that

Answer 13

ah, I'm blind sometimes!

Answer 14

ok thanks