Question

find the difference quotient of f and find f'(c) by computing the limit of the difference quotient

f(x)=2x^2 at c=2

can someone please do a step by step using x+h not some other ish. I am just not getting it.

Answer 1

I went from 2(x+h)^2-2x^2 / h to 4xh+h^2 / h factored out an h got 4x+2h can someone explain to me the last part

Answer 2

last part is letting h go to zero and getting
\[f'(x)=4x\] and so
\[f'(2)=8\]