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find the difference quotient of f and find f'(c) by computing the limit of the difference quotient f(x)=2x^2 at c=2 can someone please do a step by step using x+h not some other ish. I am just not getting it.
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I went from 2(x+h)^2-2x^2 / h to 4xh+h^2 / h factored out an h got 4x+2h can someone explain to me the last part
last part is letting h go to zero and getting \[f'(x)=4x\] and so \[f'(2)=8\]
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