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equation: log[3] (x^2 +1) = 2
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what is the inverse of the log operation?
solve for x
log[3] x(^2) + 1 = 2
what im trying to say is that the only exponent is 2
to do that we need to do something to get rid of the log on the right to get rid of a log base b, we do the following:\[\large b^{\log_3x}=x\]so we will raise the base to the power of both sides if the log is not by itself on one side of the equals sign, get it that way first
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sorry typo above*\[\huge b^{\log_bx}=x\]
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