Question

how do i find the limit

ln(x-3)
x-->3+

Answer 1

it's approaching from the right, so it's defined because x-3 is positive
and what number does lny approach as y approaches zero?

Answer 2

ln 0 = infinity

Answer 3

...because x^a is always positive for x>0
we can only make it small by making 'a' large negative

Answer 4

oh kinda get it

Answer 5

you migth think of it like this. the log is the inverse of the exponential. when would
\[e^x=0\]? well never, but it would be close to zero if x went to minus infinity

Answer 6

yes it should be minus^
Igb is a bit off

Answer 7

so as x goes to minus infinity,
\[e^x\] goes to zero and as x goes to zero,
\[\ln(x)\] goes to minus infinity