Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Twice an integer increased by fourteen is less than 5. What is the greatest solution? Please explain.

OpenStudy (anonymous):

x+14 > 5 well if you have this and solve x < 9 so i think this would be the greatest solution

OpenStudy (anonymous):

answer is -5. I don't how. Please can you try again.

OpenStudy (anonymous):

it's a multiple choice A. -5 B.-4 c.-4.5 D.- 4.6 E.NOTA

OpenStudy (anonymous):

o lol i forgot the 2 2x + 14 > 5 2 x > - 9 x > -9/ 2 x > - 5

OpenStudy (anonymous):

Answer is A

OpenStudy (anonymous):

it was 2x i forgot it XD

OpenStudy (anonymous):

wow.thanks

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

How did you get x>-5 x > -9/ 2 x > - 5 it.s x>-4.5

Directrix (directrix):

Twice an**** integer ***increased by fourteen is less than 5 ----- The answer has to be an integer. I think that the problem is set up incorrectly. Twice an integer increased by fourteen is less than 5 2x + 14 IS Less Than 5. 2x + 14 < 5 2x < - 9 x < -9/2 x < -4.5 The largest INTEGER value of x that is less than -4.5 is -5.

Directrix (directrix):

Note: Had this work been correct: x > -9/ 2, x > - 4.5, then the answer would be -4 and not -5.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!