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given -x+3y=11 find the parallel line that goes through the point (4,-2)
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y = (x/3) + (11/3) plug in (4,-2) -2 = (4/3) + b b = -3.33 y = (x/3) -3.33 try that
y=(1/3)x+11 is the form of the equation that you're given, your line has a same slope 1/3, so its equation is: y+2=1/3(x-4) so y=(1/3)x-10/3
yea what he said
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