Question

solve for x

1. x^5=31
2. x^4/3=-64
3. 27^2/3=x^1/2

Answer 1

calculator for this one

Answer 2

i'll take 3.

Answer 3

unless you mean
\[x^5=32\] in which case
\[x=2\] because
\[2^5=32\]

Answer 4

27^(2/3) is the same as 3^2 is the same as 9 .. so 9 is left side of equation

Answer 5

so 9=x^(1/2)
square both sides to find x
x=81 ..............ans.3.

Answer 6

nope, it's 31 aha!

Answer 7

for the first one:
x=31^(1/5).............ans1

Answer 8

and for the second one first take the cube root of -64=-4
then raise it to the power of 4 which is 256
x=256

Answer 9

Thanks bro :)

Answer 10

wait i think i did the second one wrong! however, there is something wrong with the question

Answer 11

well, that's what the teacher has on the paper, -__-"

Answer 12

you have to first take the 4th root of -64 and you can't take an even root of a negative number

Answer 13

unless you are dealing with complex numbers.

Answer 14

yes, not likely something raised to the fourth power will be negative