what would this be (sq rt 0f 21) * (sq rt 0f 3)

Question

anonymous · Answer

Do like the last problem and multiply the two numbers under the root together and then find any perfect squares.

anonymous · Answer

how there are no perfect roots there is 7 and 3 put neight of those are perfect squaer

anonymous · Answer

There is 7*3=21 and 3 so your factors are 7,3,3.... because the problem is $$\sqrt{21*3}$$

anonymous · Answer

both problems have the same root so you can multiply the numbers under the root together.

anonymous · Answer

im still not getting this

anonymous · Answer

What do you get if you multiply 21*3? Then what are the factors of that? Then take out any factor pairs and what is left is what stays under the square root.

anonymous · Answer

63

anonymous · Answer

1and63
3and 21 
9and 7 so i would use this one

anonymous · Answer

Right, because 9 is a perfect square and 7 doesn't have any perfect square factors.

anonymous · Answer

then what do i do with the other half of the problem

anonymous · Answer

umm what other half.... the problem was $$\sqrt{21}*\sqrt{3}$$ correct?

anonymous · Answer

Read my second post.

anonymous · Answer

ya but what do i do with the (sq rt of 3)