Question

find all roots of this equation
x^3-5x^2+2x+8=0

Answer 1

x =2, -1, 4

Answer 2

how did u do that though

Answer 3

for the 1st root you hav to find it just by substituting a satisfactory value..i.e 2. it's not hard if you hv got a proper practice.
then,
x^3-5x^2+2x+8 = (x-2)*(x^2 + bx -4)
you ll get b = -3 , i.e (x^2-3x-4) = 0 ==>> (x-4)(x+1) = 0

Answer 4

super bad at math thank you so much for your help... i kind of get it!