Question

What is the derivative of g(x) = 1/ sqrt (x) ?

Answer 1

g(x) = x^(-1/2)
g'(x) = (-1/2)*x^(-3/2)

Answer 2

g'(x) = -1/(2*x^(3/2))

Answer 3

can you show me how u get this answer..i got - 1 /x as the answer..

Answer 4

1/sqrt(x) = x^(-1/2) right?

Answer 5

yes

but i left it as square root because sqrt x and sqrt x will be x

Answer 6

why are you multiplying this by the square root?

Answer 7

1/ sqrt (x+h) - 1/ sqrt (x) x 1/h

= sqrt x - sqrt (x+h) / (sqrt (x+h) (sqrt x)

and then multiply by the conjugate which is sqrt x + sqrt x+h

Answer 8

so here all the square roots will be cancelled out

Answer 9

oh wait u're solving this using a limit definition?

Answer 10

yes

Answer 11

then how u do it with limit?