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another cal question
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\[\int\limits_{?}^{?}e ^{ax+b}\]
the power is ax+b
\[\int e^{ax} e^bdx = e^b\int e^{ax}dx\]
\[e^b\] is a constant, comes right out front
so would you mutliply the inside/outside by a and 1/a
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and let u = ax
yes that will do it
\[u=ax, du =adx, \frac{1}{a}du = dx\] get \[\int e^{ax}dx =\frac{1}{a}e^{ax}\] pretty much in your head
ok thats what i got thanks
yw
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