solve 5x^2+12=-6x using quadratic formula

Question

anonymous · Answer

Rewrite it into standard form:
5x^2+6x+12=0, you can use the quadratic formula from here

anonymous · Answer

$$x=-b \pm \sqrt{b^2-4ac}$$ over 2a

anonymous · Answer

$$\frac{-6 \pm \sqrt{6^2-4(5)(12)}}{2(5)}$$
Both solutions will be complex numbers

anonymous · Answer

$$\frac{-6 \pm \sqrt{-204}}{10}$$
$$\frac{-6 \pm i \sqrt{204}}{10} = \frac{-6 \pm 2i \sqrt{51}}{10}$$
=$$\frac{-3 \pm i \sqrt{51}}{5}$$

anonymous · Answer

what is the i for?

anonymous · Answer

Are you unfamiliar with imaginary numbers?

anonymous · Answer

i^2=-1

anonymous · Answer

no 
never used them

anonymous · Answer

Well, there are no REAL NUMBER solutions to the quadratic, but there are complex solutions

anonymous · Answer

and how do  i do that

anonymous · Answer

anonymous · Answer

If you aren't expected to know imaginary/complex numbers, then I suppose you can write no solution...

anonymous · Answer

anonymous · Answer

thanks