Question

solve 5x^2+12=-6x using quadratic formula

Answer 1

Rewrite it into standard form:
5x^2+6x+12=0, you can use the quadratic formula from here

Answer 2

\[x=-b \pm \sqrt{b^2-4ac}\] over 2a

Answer 3

\[\frac{-6 \pm \sqrt{6^2-4(5)(12)}}{2(5)}\]
Both solutions will be complex numbers

Answer 4

\[\frac{-6 \pm \sqrt{-204}}{10}\]
\[\frac{-6 \pm i \sqrt{204}}{10} = \frac{-6 \pm 2i \sqrt{51}}{10}\]
=\[\frac{-3 \pm i \sqrt{51}}{5}\]

Answer 5

what is the i for?

Answer 6

Are you unfamiliar with imaginary numbers?

Answer 7

i^2=-1

Answer 8

no
never used them

Answer 9

Well, there are no REAL NUMBER solutions to the quadratic, but there are complex solutions

Answer 10

and how do i do that

Answer 11

http://en.wikipedia.org/wiki/Complex_number

Answer 12

If you aren't expected to know imaginary/complex numbers, then I suppose you can write no solution...

Answer 13

http://en.wikipedia.org/wiki/Imaginary_numbers

Answer 14

thanks