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how would you identify the x intercepts of f(x)=25-x^2? No graphing calculator allowed.
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set 25-x^2=0
and then factor (x+5)(x-5)?
Take y=0 for finding x-intercepts. 0=25-x^2 Take x^2 to the other side, x^2=25 Or x=5
yes
so \[x=\pm 5\]
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\[x^2=25, x= \pm 5\]
Yes that's right.
thank you!
wait.. but it's a negative x..
There are 2 solutions, positive and negative 5
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OH, you moved it to the other side, gotcha
yeah no need to factor that one, pretty easy :)
wasn't thinking straight, what a simple question that was.. hahah wow. -facepalm-
It happens, because of our awesome education systems we tend to make easy things difficult sometimes.
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