Does S={(1,-1)(2,1) span R^2?
use elimination to see if there are 2 pivots
elimination? how?
What do u mean?
I'm curious, is this linear algebra or multi at your school?
my textbook never explained it to us using that method
linear algebra
neways i wld say that it does span R^2
In that case you must show that all linear combinations of (1,-1)(2,1) correspond to all linear combinations reached by (1,0), (0,1) or a matrix made of these vectors has a non-zero determinant
|dw:1328905293111:dw| or show they are not dependent (fall on the same line)
ok got it so i was correct then?
Definitely spans R^2, by the picture, you see you can reach any point by moving some distance (plus or minus) along one vector, and then some distance along the second vector.
ok i think i get it
so i guess S={(0,2)(1,4) also spans R^2
yep
ok so basically if the points are like a multiple of another then it wld form a line so it wldnt span R^2
if they can be reduced to the identity matrix/ if they are linearly independent/ if they form a matrix with a non-zero determinant they span R2 all those above things imply each other
(1,0) and (0,1) span R2, right?
kk i got it thanks.
|dw:1329769904058:dw|if you think of them in a linear combination you get the above matrix, which you can see has a non-zero determinant
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