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A student determined the heat of fusion of water to be 88 calories per gram if the accepted value is 80 calories per gram, what is the students percent error?
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it it 11% ???
Percent error is defined as...\[\delta = \frac{\left| v-v_{measured} \right|}{\left| v \right|}*100 \]Where... delta is the percent error v is the actual (or accepted) value v_measured is the value that was measured \[\delta = \frac{\left| 88 - 80 \right|}{\left| 80 \right|}*100=\frac{|8|}{|80|}*100=0.1*100=10\%\]
Oh Yeah i remember learning that in the beginning of the year! Thank You so much Again! ^.^
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