Question

find the value of 3x (over) (sqrt)x3

Answer 1

is it:
\[\frac{3x}{\sqrt{3x}} ?\]

Answer 2

yes

Answer 3

\[\frac{3x}{\sqrt{x^3}}=\frac{3x*\sqrt{x^3}}{\sqrt{x^3}*\sqrt{x^3}}\]\[=\frac{3x*\sqrt{x*x^2}}{x^3}\]\[=\frac{3x^2\sqrt{x}}{x^3}\]\[=\frac{3\sqrt{x}}{x}\]

Answer 4

thanks

Answer 5

wait is it \[\frac{3x}{\sqrt{x^3}}\] or \[\frac{3x}{\sqrt{3x}}\] ?

Answer 6

if its :
\[\frac{3x}{\sqrt{3x}} \]
then..
\[\frac{3x*\sqrt{3x}}{\sqrt{3x}*\sqrt{3x}} =>\frac{3x*\sqrt{3x}}{3x} =\sqrt{3x} \]