help 8b^2-50. Factor do i do it 8(b^2-50) or 8(b-25)(b+25) or 8(b-5)(b+5) OR none
none if you take out the 8 you have to factor it out of BOTH terms 50/8 is not a perfect square, so try to factor out 2 instead remember to factor it out of both terms first
(10a+50)=10(a+5) for example
25^2 not= 50
ok so 2(b+25)^2?
why did the ^2 move outside?
\[b\sqrt{8}\pm \sqrt{50}\]
lol I m not sure he was nt happy inside????ok so keep 2 inside?
yeah and keep it negative and b should still have a 4 next to it
(2b+25)(2b-25)
25^2 not= 50 still
no w8
...and the 2 that you pulled out needs to stay next to the parentheses it can't just disappear
not to mention the other fauxpauxs
ok thats why im on here armi have patience grasshopper
2(4b+25)(b-25)
\[(a^2-b^2)=(a+b)(a-b)\](just to make sure it's on the screen)
but 8 has no sq root you see where im stuck
let's back up... 8 and 50 are not perfect squares, but they are close divide each by 2 and they will be, so we factor out a 2:\[8b^2-50=2(4b^2-25)\]that's the first step now what is a and b in your particular problem
4 and 25?
no, that is a^2 and b^2 so what are a and b then?
I DONT KNOPWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW im sorry im challenged mathematically speaking
I dont have a clue. I thought a and b was 8 and 25 what else is there to choose from?
actually sorry my notation is confusing you perhaps the difference of squares formula is\[x^2-y^2=(x-y)(x+y)\]your formula is\[8b^2-50=2(4b^2-25)=2((2b)^2-5^2)\]so what I call x and y in the formula are 2b and 5 in your particular problem
No its not you it's me. you have been really helpful thank you. I will apply it to the next equation. thanks<3
It makes sense when you break it down like that<3
welcome you know this one's not done though, you still need to apply the actual formula for difference of squares I will leave that to you
thanks tur.
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