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Use the integral test to determine whether the series converges or diverges: ∑[n = 2,∞,(1)/(n√(n^(2) - 1))]
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\[\int_2^{\infty}\frac{1}{x\sqrt{x^2-1}}dx\] is what you want i guess
which luckly happens to be \[-\tan^{-1}(x)\] and so it converges
Oh! I didn't catch that. Thank you!
yw btw you can just about do this with your eyeballs because even though the denominator is not a polynomial, if you ignore the -1 under the radical it is pretty clear that the denominator behaves like n^2 and so you can use the comparison test. but if you told to use integral test this would do it
Comparison test as in the direct comparison test, right? Also, I was just checking my notes. Isn't the integral actually \[\sec ^{-1}n\] ?
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