1.In A Hydraulic process, a 20-kg load on the left piston will support a 600-kg load on the right piston. How does the pressure of fluid against the lower part of the left piston compare with the pressure against the lower right piston ( greater on the right, greater on the left or the same pressure on each?
2. What principle is used to answer this question #1? 1.In A Hydraulic process, a 20-kg load on the left piston will support a 600-kg load on the right piston. How does the pressure of fluid against the lower part of the left piston compare with the pressure against the lower right piston

Question

anonymous · Answer

the pres is equal, the amount of load able to be carried is dependent on the surface are of the piston but the fluid pressure on both sides are equal. or i dunno, didnt get all of the way through college but thats my best guess. the surface area of the 600 kg load is 30 times greater than the piston with the 20 kg load?

anonymous · Answer

The pressures in a hydraulic system must be equal. $$P_A = P_B$$ We know that pressure is defined as $$P = {F \over A}$$From these two relations, we can find the area of each side of the hydraulic system.

anonymous · Answer

THE PRINCIPLE IS USING PASCALS LAW THAT THE PRESSURE EXERTED ON fluid in equilaibrium is transmitted undininshed to al its parts(here the same pressure from left to right)
also note that if 600kg is to lifted,
then pressure shud be equal thatr bis
200/a1=6000/a2
implying that a2>a1