Question

Young's double-slit question?

Answer 1

Given that the frequency of light is so high, why are the bands relatively large (millimetres)?
Surely their phases would interfere/reinforce each other at MUCH smaller intervals (nanometres)?

Answer 2

from v=fj where j=wavelength ,then a high frequency implies a low wavelength and since for a good diffraction or constructive interference the diameter of the openings must be equal or smaller than the distance between the wavelengths of the ligth .hence the bands are made smaller to have a food diffraction of the light.hence we can get a better interference pattern on the screen

Answer 3

i hope that helped u

Answer 4

But the wavelength of light is about 500nm, whereas the bands are mm across. Why is this?

Answer 5

you are rigth but do not forget that it depends on the light bcuz red light has a different wavelength than blue light an so on .so be sur of the light u are telling.

Answer 6

However, all visible light (the type that Young saw, because we cannot see radio waves etc.)'s wavelengths are in the region of nanometres. So I meant any visible light: surely even for the lowest frequency visible light the problem would still be there.