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Linear Algebra: System of Linear Equations. How do I solve for variables in the denominator? Example such as the system of linear equations: (2/x)+ (3/y)+ (4/z)= 1 (9/x)+ (4/y)- (4/z)= 0 (7/x)+ (9/y)- (3/z)= 6
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doesnt matter; same process only instead of =x, you do =1/x
That is where I am a bit confused. How would I type the augmented matrix?
2 3 4 1 9 4 4 0 7 9 3 6 id assume
You assume. Alright, thank you for trying.
i forgot the negatives :)
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the wolf rrefs it to: http://www.wolframalpha.com/input/?i=rref%7B%7B2%2C+3%2C+4%2C+1%7D%2C%7B9%2C+4%2C+-4%2C+0%7D%2C%7B+7%2C+9%2C+-3%2C+6%7D%7D sooo: x^-1 = -144/257 y^-1 = 263/257 z^-1 = -61/257
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