Question

sqrtx(3x+0), what is the derivative?

Answer 1

please show calc

Answer 2

\[\sqrt{x}(3x+0)\]

Answer 3

ive got 9/2x ^1/2

Answer 4

You want the derivative of that or the other one?

Answer 5

i want the derivative of the entire f(x)=\[\sqrt{x}(3x+0)\]

Answer 6

\[3x^{3/2}\]
Derivative:
\[\frac{3}{2}3x^{1/2}=\frac{9}{2}\sqrt{x}\]

Answer 7

can you explain how you did it pls

Answer 8

product rule = uv'+vu'
u=sqrtx or x^(1/2)
u'=.5x^(-1/2)
v=3x
v'=3
(x^(1/2))(3)+(3x)(.5^(-1/2))
simplify

Answer 9

I've got the same answer as you, you were right

Answer 10

rickjbr, my teacher wrote that answer on the board. i just didnt understand how he arrived there

Answer 11

I just distribute the sqrt(x) to the parentheses and took the derivative of that

Answer 12

\[\sqrt{x}(3x+0)=3(x)^{3/2}\]
Then take the derivative:
Multiply the exponent by the constant and subtract 1 from the exponent:
Derivative:
\[\frac{3}{2}*3x^{1/2}\]

Answer 13

\[\frac{3}{2}3x^{3/2-2/2}=\frac{9}{2}\sqrt{x}\]

Answer 14

thanks