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How to find the sum of the coefficients for 5x2 + 4xy – 3(x +2). Please explain.
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How to find the sum of the coefficients for 5x^2 + 4xy – 3(x +2). Please explain.
so it can be zero
the coefficients in this expression are the numbers
Please can you explain
sorry not all the numbers - only those in front of variables so they are 5, 4 and -3
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sum of these = 6
so -6 is the constant number
yea
but the answer for this question is zero
oh ok - so they have included -6. You can regard a constant as the coefficient of x^0 that is 1. -6 = 6x^0.
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-6 = -6x^0.
Thank you.I always learned that number without variable is constant.but it excludes for for only quadratic equations . Is it right
sorry but i'm not really sure - it appears that way.
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