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using 15degrees=45degrees-30 degrees what would be the sin, cos and tan of 15 degrees?
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sin(a+ -b) = sin(a)cos(-b) + sin(-b)cos(a) cos(a+ -b) = cos(a)cos(-b)-sin(a)sin(-b) and tan = sin/cos
tan(a+b) tan(a)tan(b) ---------- 1+tan(a)tan(b) maybe
sin(45-30)=sin45cos30-cos45sin30 cos(45-30)=cos45cos30+sin45sin30
whats a and b?
a and b are representative of whatever angles you are working with. In this case a is 45 and b is 30
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yep
well, i went ahead and used -b for -30
otherwise Im sure I would have messed up the operation in the middle :)
got it
im having problems with tangent
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