Question

HELPPPP

Answer 1

What do you need help with?? Where are you stuck?

Answer 2

minimum points of what?

Answer 3

f(x) = cos 2x − 2 sin x

Answer 4

what she said

Answer 5

Are you guys doing the same problem or something??

Answer 6

Gals*

Answer 7

yes

Answer 8

Ahh I dont know the answer sorry.

Answer 9

it's okay

Answer 10

thanks anyway :)

Answer 11

Np :D

Answer 12

without using a graphing package, you can differentiate
f' = -2sin(2x) - 2cosx
the maximum height will occur when f'=0, that is
-2sin(2x) - 2cosx = 0; divide through by -2
sin(2x) + cosx = 0; expand sin(2x)
2sinx.cosx + cosx = 0; divide through by cosx
2sinx + 1 = 0
2sinx = -1
sinx = -1/2, so the stationary points on the graph will occur for reference angle pi/6, with two values of x, one between pi & 3pi/4 & the other between 3pi/4 & 2pi.
I'm a bit short of time, so plug those values into your calculator to find your answer - it's likely that one will be a maximum & the other a minimum.

Answer 13

Wolfram says min is -3 at x = pi/2 +2npi

Answer 14

Which makes sense because min of cos2x is -1 and max of sin is 1 so max of 2sin is 2 and -1-2 is -3

Answer 15

i dont understand, what would be x? for max

Answer 16

I thought you wanted the minimum?

Answer 17

i need both

Answer 18

Since you are subtracting, the minimum of the function will be when the first term is a minimum and the second term is a maximum. What is the minimum value for cos2x? What is the maximum value for 2sinx? Subtract. That will be your minimum