hat do you call a problem such as : solver the following for 'y' 3y-2/5 = 6y-5/11 i am trying to find a video to help me understand this

Question

mimi_x3 · Answer

Is it: 
$$\large \frac{3y-2}{5}   = \frac{6y-5}{11}  $$

anonymous · Answer

yes  that is what it looks like

mimi_x3 · Answer

Can you cross multiply it?

anonymous · Answer

i don't know how to figure it...

mimi_x3 · Answer

$$(3y-2)*11$$
for the first side. 
can you do the other side?

anonymous · Answer

(6y - 5) + 5
?

mimi_x3 · Answer

No, when you cross multipply its times.
$$(6y-5)\times5$$

anonymous · Answer

so this may be stupid... but the = sign doesn't mean you do things separately?

anonymous · Answer

so basically you are just doing it as a cross multiply with the other problem, is that what you mean?  the equal sign isn't going seperating the problems...

mimi_x3 · Answer

Hm..its like this: 

$$11(3y-12)=5(6y-5)$$

I was just trying to make it easier understand i failed i suppose xD

anonymous · Answer

oh no... it helps me to try to think it through... you were awesome!! ok, so i think i understand it... what exactly do you call this type of problem?

mimi_x3 · Answer

Well, from that just expand it; and collect the like terms. Can you do that? 

Um..I forgot the name of it sorry.

anonymous · Answer

yes, i get it now!  
thank yoou soooo much!!!

mimi_x3 · Answer

np.
Just ask me if you need more help (: