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The number of bacteria present in a culture after t minutes is given as B=10e^kt. If there are 4497 bacteria present after 13 mintutes, find k.
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4497=10e^(k13)
ln(B/10) ------- = k 13
soo; k = ln(449.7)/13
Thanks! :) So that is the answer? ^^ I don't have to simplify further?
i dont know what you HAVE to do to it; but thats the exact answer; simplify or approx as directed by your material
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