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Find sum of (7/(6x^2y))+(3/(2xy^2))
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first of all...your LCD is 6x^2y^2...it's pretty easy from there on..can you do it? :D
haha, let me see.
7y+9x
nope :p haha. you're missing the denominator
ooohh yeah. lol. so is it 7y+9x/6x^2y^2
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yes.
thanks!!! you're soooo helpful! you're a life saver. :)
^_^
so how does this one work.. (9+2x)/(a^2b^2c) find equivalent that has a denominator of a a^2b^2c^2
your multiplying your denominator by c...that's why it got squared...so for equality, multiply the numerator by c...don't forget to distribute
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9c+2c^2
was that wrong?
again...you forgot the denominator
lol. sorrry. 9c+2c^2/a^2b^2c^2
and also it should be 9c + 2xc not c^2
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2xc? ooohh okay. sorry about that. thank you
2xc or 2*c?
waittt, nvm!
you got it? ok
thank you. :)
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