Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
write the expression in factored form 5x^2+5 my answer is 5(x^2+1)
OpenStudy (anonymous):
the only thing the two terms have in common is the 5, so you are correct
OpenStudy (pokemon23):
i got more questions
OpenStudy (anonymous):
go for it
OpenStudy (pokemon23):
awesome :D
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
factor b^2+4b+3
OpenStudy (pokemon23):
my answer is (b+4) (b+3)
OpenStudy (anonymous):
Correct!
OpenStudy (pokemon23):
hi andrew did you read the article
OpenStudy (anonymous):
Wait no
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
For the answer part
OpenStudy (pokemon23):
it will explain evryhting you need to know about this site
OpenStudy (anonymous):
I know, I'll get to it
OpenStudy (anonymous):
But for your answer, think of factors that multiply to 3 and add to 4
OpenStudy (pokemon23):
my next question is factor x^2-12x+11
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
wait im wrong?
OpenStudy (anonymous):
Yeah you're wrong
OpenStudy (anonymous):
Sorry, read it wrong
OpenStudy (pokemon23):
(b+3) (b+1)
OpenStudy (anonymous):
Correct for real this time
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
ok the second question answer is (x-1) (x+11)
OpenStudy (anonymous):
Very close
OpenStudy (pokemon23):
i got it
OpenStudy (anonymous):
No, it's not, it should be (x - 1)(x - 11)
OpenStudy (pokemon23):
(x-11) (x-1)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
beat me first
OpenStudy (anonymous):
In what?
OpenStudy (pokemon23):
answering the question
OpenStudy (pokemon23):
well you did get 2 place
OpenStudy (anonymous):
Show you how?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
WHAT IS GOING ON!?
OpenStudy (pokemon23):
noting?
OpenStudy (anonymous):
?
OpenStudy (pokemon23):
the next question is b^2-2b-8
OpenStudy (anonymous):
What's your answer?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
(b-2) (b+4)
OpenStudy (anonymous):
So close again!
OpenStudy (pokemon23):
-_-
OpenStudy (anonymous):
Your answer whould result in the trinomial b^2 + 2b - 8.
OpenStudy (anonymous):
(b - 4)(b +2). That's the answer to this.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
AWWWWWWWWW
OpenStudy (anonymous):
Yeah
OpenStudy (anonymous):
How do you calculate your answers?
OpenStudy (pokemon23):
i do it in my mind
OpenStudy (anonymous):
Uh...I do it in my mind because I've done it like a million times, but since you're just starting, shouldn't you do it on paper until you get the hang of it?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
I see your point ..... I guess your right maybe I should slow down
OpenStudy (pokemon23):
my next question is 2x^2+5x+2
OpenStudy (anonymous):
If you feel confident enough that you think you can do it, just start off by writing down important stuff so that you don't overload your mind. Basically write down loose numbers.
OpenStudy (anonymous):
And to the problem, we finally get to the grouping! Not even I do this in my head.
OpenStudy (pokemon23):
I see thanks might used them in my upcoming test on Tuesday
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
i don't know how to do this I only this part 2(x^2+?+1)
OpenStudy (anonymous):
Why are you taking out the 2?
OpenStudy (anonymous):
There's no GCF
OpenStudy (pokemon23):
ohhh
OpenStudy (anonymous):
Do you get it now?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
not really wanna skype
OpenStudy (pokemon23):
me and my tutor do this
OpenStudy (pokemon23):
he explains to me manually
OpenStudy (pokemon23):
in talking
OpenStudy (anonymous):
So basically, because 2x^2+5x+2 has a leading x^2 with a coefficient, you multiply the squared variable with the constant and find 2 factors that multiply to this product and add up to 5 since it's the middle term.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So find factors that multiply to 4 and add upp to 5.
OpenStudy (pokemon23):
4 and 1
OpenStudy (anonymous):
Do you understand so far?
OpenStudy (pokemon23):
yes ;D
OpenStudy (anonymous):
Now reinsert these factors in the place of 5x like so: 2x^2 + 4x + x + 2. (Note, the order that they're inserted doesn't matter as long as they are in the middle.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
With me at this point?
OpenStudy (pokemon23):
yes
OpenStudy (anonymous):
Ok, now group the first two terms and the second 2 terms. (2x^2 + 4x) + (x + 2). Now factor out the GCF of both of these binomials separately. The result should be 2x(x + 2) + (x + 2).
OpenStudy (pokemon23):
so we get (4x+2x)+ (2x)
OpenStudy (anonymous):
No matter what happens, the two binomials inside the parenthases should be the same. If they aren't look for an error. (A common mistake is leaving a negative inside, so all you would have to do is also factor out the negative as well.) And we still aren't done, so your answer is incorrect.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Do you get it?
OpenStudy (pokemon23):
-_- kind of?
OpenStudy (anonymous):
What part is confusing you?
OpenStudy (pokemon23):
keep going...
OpenStudy (pokemon23):
Ok, now group the first two terms and the second 2 terms. (2x^2 + 4x) + (x + 2). Now factor out the GCF of both of these binomials separately. The result should be 2x(x + 2) + (x + 2).
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Yeah, but what part of it?
OpenStudy (pokemon23):
that is the part
OpenStudy (anonymous):
Do you get grouping the first and last 2 terms together?
OpenStudy (pokemon23):
ummm no?
OpenStudy (anonymous):
Alright, you have a 4 term polynomial when you insert the factors in again right?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
i know to get 5 we got 4x and 1x
OpenStudy (anonymous):
Alright, because 4x + 1x = 5x, it can replace 5x right? That's what we did there.
OpenStudy (pokemon23):
yes
OpenStudy (anonymous):
So at that point, you should have 2x^2 + 4x + x + 2 right?
OpenStudy (pokemon23):
yes
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Now, what you're supposed to do here is put parentheses around the first two terms: (2x^2 + 4x) and the last two terms: (x + 2) separated by an addition sign.
OpenStudy (pokemon23):
k but why do we put them in parentheses
OpenStudy (anonymous):
This is why this process is called "grouping" it's just a part of the process.
OpenStudy (pokemon23):
ok..
OpenStudy (anonymous):
Do you get it?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
yes then we foil?
OpenStudy (anonymous):
No.
OpenStudy (pokemon23):
ok..?
OpenStudy (pokemon23):
what's the next step..?
OpenStudy (anonymous):
What we have at this point is (2x^2 + 4x) + (x + 2) right?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
yes
OpenStudy (anonymous):
Now, find the GCF of both binomials SEPARATELY.
OpenStudy (anonymous):
For the first binomial, you can factor out 2x because there it is common right?