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Mathematics 7 Online
OpenStudy (pokemon23):

PIE GUY MATH QUESTIONS

OpenStudy (pokemon23):

write the expression in factored form 5x^2+5 my answer is 5(x^2+1)

OpenStudy (anonymous):

the only thing the two terms have in common is the 5, so you are correct

OpenStudy (pokemon23):

i got more questions

OpenStudy (anonymous):

go for it

OpenStudy (pokemon23):

awesome :D

OpenStudy (pokemon23):

factor b^2+4b+3

OpenStudy (pokemon23):

my answer is (b+4) (b+3)

OpenStudy (anonymous):

Correct!

OpenStudy (pokemon23):

hi andrew did you read the article

OpenStudy (anonymous):

Wait no

OpenStudy (anonymous):

For the answer part

OpenStudy (pokemon23):

it will explain evryhting you need to know about this site

OpenStudy (anonymous):

I know, I'll get to it

OpenStudy (anonymous):

But for your answer, think of factors that multiply to 3 and add to 4

OpenStudy (pokemon23):

my next question is factor x^2-12x+11

OpenStudy (pokemon23):

wait im wrong?

OpenStudy (anonymous):

Yeah you're wrong

OpenStudy (anonymous):

Sorry, read it wrong

OpenStudy (pokemon23):

(b+3) (b+1)

OpenStudy (anonymous):

Correct for real this time

OpenStudy (pokemon23):

ok the second question answer is (x-1) (x+11)

OpenStudy (anonymous):

Very close

OpenStudy (pokemon23):

i got it

OpenStudy (anonymous):

No, it's not, it should be (x - 1)(x - 11)

OpenStudy (pokemon23):

(x-11) (x-1)

OpenStudy (pokemon23):

beat me first

OpenStudy (anonymous):

In what?

OpenStudy (pokemon23):

answering the question

OpenStudy (pokemon23):

well you did get 2 place

OpenStudy (anonymous):

Show you how?

OpenStudy (anonymous):

WHAT IS GOING ON!?

OpenStudy (pokemon23):

noting?

OpenStudy (anonymous):

?

OpenStudy (pokemon23):

the next question is b^2-2b-8

OpenStudy (anonymous):

What's your answer?

OpenStudy (pokemon23):

(b-2) (b+4)

OpenStudy (anonymous):

So close again!

OpenStudy (pokemon23):

-_-

OpenStudy (anonymous):

Your answer whould result in the trinomial b^2 + 2b - 8.

OpenStudy (anonymous):

(b - 4)(b +2). That's the answer to this.

OpenStudy (pokemon23):

AWWWWWWWWW

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

How do you calculate your answers?

OpenStudy (pokemon23):

i do it in my mind

OpenStudy (anonymous):

Uh...I do it in my mind because I've done it like a million times, but since you're just starting, shouldn't you do it on paper until you get the hang of it?

OpenStudy (pokemon23):

I see your point ..... I guess your right maybe I should slow down

OpenStudy (pokemon23):

my next question is 2x^2+5x+2

OpenStudy (anonymous):

If you feel confident enough that you think you can do it, just start off by writing down important stuff so that you don't overload your mind. Basically write down loose numbers.

OpenStudy (anonymous):

And to the problem, we finally get to the grouping! Not even I do this in my head.

OpenStudy (pokemon23):

I see thanks might used them in my upcoming test on Tuesday

OpenStudy (pokemon23):

i don't know how to do this I only this part 2(x^2+?+1)

OpenStudy (anonymous):

Why are you taking out the 2?

OpenStudy (anonymous):

There's no GCF

OpenStudy (pokemon23):

ohhh

OpenStudy (anonymous):

Do you get it now?

OpenStudy (pokemon23):

not really wanna skype

OpenStudy (pokemon23):

me and my tutor do this

OpenStudy (pokemon23):

he explains to me manually

OpenStudy (pokemon23):

in talking

OpenStudy (anonymous):

So basically, because 2x^2+5x+2 has a leading x^2 with a coefficient, you multiply the squared variable with the constant and find 2 factors that multiply to this product and add up to 5 since it's the middle term.

OpenStudy (anonymous):

So find factors that multiply to 4 and add upp to 5.

OpenStudy (pokemon23):

4 and 1

OpenStudy (anonymous):

Do you understand so far?

OpenStudy (pokemon23):

yes ;D

OpenStudy (anonymous):

Now reinsert these factors in the place of 5x like so: 2x^2 + 4x + x + 2. (Note, the order that they're inserted doesn't matter as long as they are in the middle.

OpenStudy (anonymous):

With me at this point?

OpenStudy (pokemon23):

yes

OpenStudy (anonymous):

Ok, now group the first two terms and the second 2 terms. (2x^2 + 4x) + (x + 2). Now factor out the GCF of both of these binomials separately. The result should be 2x(x + 2) + (x + 2).

OpenStudy (pokemon23):

so we get (4x+2x)+ (2x)

OpenStudy (anonymous):

No matter what happens, the two binomials inside the parenthases should be the same. If they aren't look for an error. (A common mistake is leaving a negative inside, so all you would have to do is also factor out the negative as well.) And we still aren't done, so your answer is incorrect.

OpenStudy (anonymous):

Do you get it?

OpenStudy (pokemon23):

-_- kind of?

OpenStudy (anonymous):

What part is confusing you?

OpenStudy (pokemon23):

keep going...

OpenStudy (pokemon23):

Ok, now group the first two terms and the second 2 terms. (2x^2 + 4x) + (x + 2). Now factor out the GCF of both of these binomials separately. The result should be 2x(x + 2) + (x + 2).

OpenStudy (anonymous):

Yeah, but what part of it?

OpenStudy (pokemon23):

that is the part

OpenStudy (anonymous):

Do you get grouping the first and last 2 terms together?

OpenStudy (pokemon23):

ummm no?

OpenStudy (anonymous):

Alright, you have a 4 term polynomial when you insert the factors in again right?

OpenStudy (pokemon23):

i know to get 5 we got 4x and 1x

OpenStudy (anonymous):

Alright, because 4x + 1x = 5x, it can replace 5x right? That's what we did there.

OpenStudy (pokemon23):

yes

OpenStudy (anonymous):

So at that point, you should have 2x^2 + 4x + x + 2 right?

OpenStudy (pokemon23):

yes

OpenStudy (anonymous):

Now, what you're supposed to do here is put parentheses around the first two terms: (2x^2 + 4x) and the last two terms: (x + 2) separated by an addition sign.

OpenStudy (pokemon23):

k but why do we put them in parentheses

OpenStudy (anonymous):

This is why this process is called "grouping" it's just a part of the process.

OpenStudy (pokemon23):

ok..

OpenStudy (anonymous):

Do you get it?

OpenStudy (pokemon23):

yes then we foil?

OpenStudy (anonymous):

No.

OpenStudy (pokemon23):

ok..?

OpenStudy (pokemon23):

what's the next step..?

OpenStudy (anonymous):

What we have at this point is (2x^2 + 4x) + (x + 2) right?

OpenStudy (pokemon23):

yes

OpenStudy (anonymous):

Now, find the GCF of both binomials SEPARATELY.

OpenStudy (anonymous):

For the first binomial, you can factor out 2x because there it is common right?

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